Question

I need help on this saturday guys

Answer 1

The point-slope form:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - the point

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have the points (5, 4) and (2, -2). Substitute:

`m=(-2-4)/(2-5)=(-6)/(-3)=2`

`y-4=2(x-5)` - point-slope form

`y-4=2x-10` add 4 to both sides

`y=2x-6` - slope-intercept form

`y=2x-6` subtract 2x from both sides

`-2x+y=-6` change the signs

`2x-y=6` - standard form

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From the table we have two points (1, 3) and (2, 7). SubstituteL

`m=(7-3)/(2-1)=(4)/(1)=4`

`y-3=4(x-1)` - point-slope form

`y-3=4x-4` add 3 to both sides

`y=4x-1` - slope-intercept form

`y=4x-1` subtract 4x from both sides

`-4x+y=-1` change the signs

`4x-y=1` - standard form