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Given: △ABC is equilateral, △ADC is isosceles,

AC
- base
Perimeter of △ABC = 36
Perimeter of △ADC = 40
Find: The length of each side of ABC and ADC

User Tessa Lau
by
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1 Answer

3 votes

Answer:


Explanation:

Since ABC is an equilateral triangle, thus AB=BC=AC=x, therefore

The perimeter of ΔABC=36

⇒AB+BC+AC=36

⇒x+x+x=36

⇒3x=36

⇒x=12

Thus, AB=BC=AC=12.

Now, Since ΔADC is isosceles triangle, therefore AD=DC=y.

Perimeter of ΔADC=40

⇒AD+DC+CA=40

⇒x+y+y=40

⇒12+2y=40

⇒2y=28

⇒y=14

Therefore, AD=DC=14

Thus, Length of sides of ΔABC are AB=BC=AC=12 and Length of sides of ΔADC are AD=DC=14.

Given: △ABC is equilateral, △ADC is isosceles, AC - base Perimeter of △ABC = 36 Perimeter-example-1
User Ratmalwer
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6.3k points