Question

Divide..................

Answer 1

option-A

Explanation:

we are given

Dividend is

`6x^2-19x+10`

Divisor is

`2x-5`

we can use long division method

we get

Remainder is

=0

Quotient is

`3x-2`

so, we can write as

`(6x^2-19x+10)/(2x-5)=3x-2+(0)/(2x-5)`

`(6x^2-19x+10)/(2x-5)=3x-2`