Question

Find the 32nd term of the arithmetic sequence.

a1 = 6.6, d = 3.6

A. 111.6
B. 121.8
C. 118.2
D. 108.2

Answer 1

`\bf n^(th)\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^(th)\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=6.6\\ d=3.6\\ n=32 \end{cases} \\\\\\ a_(32)=6.6+(32-1)3.6\implies a_(32)=6.6+(31)3.6 \\\\\\ a_(32)=6.6+111.6\implies a_(32)=118.2`