Question

What is the equation of this graphed line?

Enter your answer in slope-intercept form in the box.

Answer 1

The slope-intercept form:

`y=mx+b`

m - slope

b - y-intercept

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have the points (2, 6) and (-4, -6). Substitute:

`m=(-6-6)/(-4-2)=(-12)/(-6)=2`

Therefore we have the equation

`y=2x+b`

Put the coordinates of the point (2, 6) to the equation:

`6=2(2)+b`

`6=4+b` subtract 4 from both sides

`2=b\to b=2`

Answer:
`\boxed{y=2x+2}`

Answer 2

y = 2x+2

Explanation:

We have two points so we can find the slope

m = (y2-y1)/(x2-x1)

= (6--6)/ (2--4)

= (6+6)/(2+4)

=12/6

=2

We can use point slope form to make an equation of a line

y-y1 = m(x-x1)

y--6 = 2(x--4)

y+6 =2(x+4)

Distribute

y+6 = 2x+8

Subtract 6 from each side

y+6-6 = 2x+8-6

y = 2x+2

This is in slope intercept form

y= mx+b