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Which is equivalent to \sqrt[3]{8}^{\frac{1}{4}x} ?
a. 8^{\frac{3}{4}x}
b. \sqrt[7]{8}^{x}
c. \sqrt[12]{8}^{x}
d. 8^\frac{3}{4x}

User Farrad
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2 Answers

3 votes

Answer:

Explanation:

It takes a while to understand but the answer is c because if you reverse [3][8] by [1]4]x you add them together get [7][8]^[x] :)

User Jjames
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2 votes

The usual convention is to write
\sqrt[n]x=x^(1/n). So


\sqrt[3]{8^(x/4)}=\left(8^(x/4)\right)^(1/3)=8^(x/12)=\sqrt[12]{8^x}

and the answer is C.

User Anish Varghese
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5.2k points