Question

Refer to the following Diagram to answer this question In the Diagram,if the lightbulb is placed at D and B is closed( As shown) What will happen.

Answer 1

When light bulb is placed at the position of D and switch B is closed

So here the circuit is closed and there will be current flow through the circuit

So here we can use ohm's law

`V = iR`

here we have

V = voltage of battery

R = resistance of bulb

so we will got the current "i" in the circuit

so now we will have power across the bulb as

`P = V i`

`P = V((V)/(R))`

`P = (V^2)/(R)`

so bulb will glow with the power we got in above expression after connecting into the circuit