For this case we must factor.
Numerator:
![2x ^ 2 + 13x + 20](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nvmfe2lpg9djv1cdh22fegdz1l7w0n0xnp.png)
We must change the term of the medium by the sum of two numbers that when multiplied give as result
, and when summed give as result +13.
These numbers are: 5 and 8
![(5) (8) = 40\\5 + 8 = 13](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n11mjpbiugi8pf55pffvhm05orj7w1guek.png)
So:
![2x ^ 2 + 8x + 5x + 20](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q9kdoaja5yd0twu0ukhw70nuwwp2wqk9j4.png)
We take common factor on both sides:
![2x (x + 4) +5 (x + 4)\\(2x + 5) (x + 4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/424eijm72tsu6rpj92s4j34vn76n1uhu7y.png)
So,
![2x ^ 2 + 13x + 20 = (2x + 5) (x + 4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rjp7kvucggyuf8i8zvd6rqhg4ezvs3stw1.png)
Denominator:
![x ^ 2-5x-36](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t87om4ngv4my62rm3z9jgr27zeyg3oo1gw.png)
We should look for two numbers that multiplied give -36 and added as a result -5.
-9 and +4
Thus,
![x ^ 2-5x-36 = (x-9) (x + 4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fno6qvvn383jx4emkvguvcx9loay6e1kyf.png)
Then,
![\frac {2x ^ 2 + 13x + 20} {x ^ 2-5x-36} =](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xhhz9dsc04euv0ivzesl1qleoifuor45wy.png)
![\frac {(2x + 5) (x + 4)} {(x-9) (x + 4)} =\\\frac {(2x + 5)} {(x-9)} =](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5ckpzuuhv6x7i731itsy1cnkhtj2vcndes.png)
Answer:
![\frac {(2x + 5)} {(x-9)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/us47zv64qtpxb6803l58mpbhh05bubddcc.png)