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According to the fundamental theorem of algebra how many zeros does the function f(x)=15x^23+41x^19+13x^5-10
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According to the fundamental theorem of algebra how many zeros does the function f(x)=15x^23+41x^19+13x^5-10
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Sep 17, 2020
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According to the fundamental theorem of algebra how many zeros does the function f(x)=15x^23+41x^19+13x^5-10
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Gabe Halsmer
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According to the fundamental theorem of algebra, that function has 23 zeros.
Whatever degree the polynomial is, that is how many zeros it will have.
Hope I helped!
DroidT
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Sep 20, 2020
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