Question

a planter box in the city plaza measures 3 2/3 feet by 4/18 feet by 2 1/2 feet. find the volume of the planter box

Answer 1

The volume of the planter box=
`2(1)/(27)` cubic feet.

Explanation:

Given the dimensions of planter cuboid box:

Length of planter box =
`3(2)/(3)` feet.

Breath of planter box=
`(4)/(18)` feet.

Height of planter box=
`2(1)/(2)` feet.

Formula used for volume of cuboid box= (length×breath×height).

Plugging the values in above formula for volume,we get

Volume of box=
`3(2)/(3)`×
`(4)/(18)`×
`2(1)/(2)`.

Let us convert mixed fractions in to improper fractions first

Therefore,

`3(2)/(3)` feet=
`(11)/(3)`

`2(1)/(2)` feet =
`(5)/(2)`

volume =
`(11)/(3)`×
`(4)/(18)`×
`(5)/(2)`

=
`(11 * 5 * 4)/(3 * 2 * 18)`

=
`(220)/(108)`

=
`2(1)/(27)` cubic feet.

Therefore, the volume of the planter box=
`2(1)/(27)` cubic feet.

Answer 2

`V=(55)/(27)ft^3`

Explanation:

We are given box

whose dimensions are

Length is 3 2/3 feet

so,

`L=3(2)/(3) =(3* 3+2)/(3)=(11)/(3)`

Width is 4/18 feet

`W=(4)/(18)`

Height is 2 1/2 feet

so,

`H=2(1)/(2) =(2* 2+1)/(2)=(5)/(2)`

now, we can find volume

`V=L* W* H`

now, we can plug values

`V=(11)/(3)* (4)/(18)* (5)/(2)`

now, we can simplify it

and we get

`V=(55)/(27)ft^3`