374,732 views
25 votes
25 votes
2. Find four consecutive integers such that six times the sum of the first and third is 12

greater than 9 times the fourth.

User Saravanan I M
by
3.3k points

1 Answer

16 votes
16 votes

Answer:

9

Explanation:

a,a+1,a+2,a+3,...

6(a+(a+2))=12+9(a+3)

6(2a+2)=12+9a+27

12a+12=12+9a+27

12a-9a=27

3a=27

a=9

User Peter Bartels
by
2.7k points