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Solutions for 2x^2+18x=20, worth a TON, please only 100% answers ! Thank u !

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Answer:

The solution of the given quadratic equation is 1 and (-10).

Explanation:


2x^2+18x=20


x^2+9x=(20)/(2)


x^2+9x-10=0


ax^2+bx+c=0

Solving equation by quadratic formula:

Here , a = 1,b = 9, c = (-10)


D=b^2-4ac=(9)^2-4(1)(-10)=121


x=\frac{-b+{√(D)}}{2a}=((-9)+√(121))/(2(1))=1


x=\frac{-b-{√(D)}}{2a}=((-9)-√(121))/(2(1))=(-10)

The solution of the given quadratic equation is 1 and (-10).

User Tundey
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