Question

What is the this expression in standard form?: 6(5r-4)-2(r-7s-3)

Answer 1

Use distrubutive property a(b + c) = ab + ac

6(5r - 4) - 2(r - 7s - 3)

= (6)(5r) + (6)(-4) + (-2)(r) + (-2)(-7s) + (-2)(-3)

= 30r - 24 - 2r + 14s + 6

= (30r - 2r) + 14s + (-24 + 6)

= 28r + 14s - 18