Question

Help plz !!!
answers??

Answer 1

Part 1)
`y=-2x-1`

Part 2)
`y=-(1/2)x+(5/2)`

Explanation:

Part 1)

we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

`m1*m2=-1`

Find the slope of the given line

we have

`y=(1)/(2)x-1`

the slope of the given line is
`m1=(1/2)`

Find the slope of the line perpendicular to the given line

`(1/2)*m2=-1`

`m2=-2`

Find the equation of the line into slope intercept form

`y=mx+b`

we have

`m=-2`

`point (-2,3)`

substitute and solve for b

`3=-2(-2)+b`

`3=4+b`

`b=-1`

The equation is equal to

`y=-2x-1`

Part 2)

we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

`m1*m2=-1`

Find the slope of the given line

we have

`y+1=2(x-3)` -----> equation of the line into point slope form

the slope of the given line is
`m1=2`

Find the slope of the line perpendicular to the given line

`(2)*m2=-1`

`m2=-(1/2)`

Find the equation of the line into slope intercept form

`y=mx+b`

we have

`m=-(1/2)`

`point (5,0)`

substitute and solve for b

`0=(-1/2)(5)+b`

`b=5/2`

the equation is equal to

`y=-(1/2)x+(5/2)`