Question

Use the quadratic formula to find the zeros.
3x^2=8x+1

Answer 1

• x1 = 2.7863
• x2 = - 0.11963

Explanation:

Transform the quadratic to

3x^2 - 8x - 1 = 0

I don't see any obvious factors to this equation so we need to use the quadratic equation.

`\text{x = }\frac{ -b \pm \sqrt{b^(2) - 4ac } }{2a}`

• a = 3
• b = -8
• c = - 1

`\text{x = }( 8 \pm √((-8)^2 - 4*3*(-1) ) )/(2*3)`

`\text{x = }(( 8) \pm √(64 +12 ) )/(6)`

`\text{x = }(( 8) \pm √(76 ) )/(6)`

x = (8 +/- 8.7178 ) / 6

x1 = (16.87178)/6 = 2.7863

x2= (8 -8.7178)/6 = -0.1196