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A group of hikers walked 2 3/5 miles along a hiking trail. Another group of hikers walked 1/2 that distance with the first group before turning off onto another trail. How many miles did the two groups of hikers walk with each other?

2 Answers

2 votes

To find out how many miles the two groups of hikers walked with each other, we will start by determining the distance the first group walked and then calculate half of that distance for the second group.

The first group walked 2 3/5 miles. Let's firstly convert this mixed fraction to an improper fraction to make calculations easier:

2 3/5 = (2 * 5 + 3) / 5
= (10 + 3) / 5
= 13/5 miles

Now, the second group of hikers walked half that distance. So, we'll take half of 13/5:

(1/2) * (13/5) miles
= (1 * 13) / (2 * 5) miles
= 13 / 10 miles
= 1.3 miles

Hence, the two groups of hikers walked together for 1.3 miles before the second group turned off onto another trail.

User Danesh
by
5.6k points
5 votes

Answer:

Final answer is
1 (3)/(10) miles.

Explanation:

Given that a group of hikers walked
2 (3)/(5) miles along a hiking trail. Another group of hikers walked
(1)/(2) that distance with the first group before turning off onto another trail. Now we need to fnd about how many miles did the two groups of hikers walk with each other.

To find that we just need to find half of
2 (3)/(5)

=
(1)/(2)\left(2(3)/(5)\right)

=
(1)/(2)\left((13)/(5)\right)

=
(1*13)/(2*5)

=
(13)/(10)

=
1 (3)/(10)

Hence final answer is
1 (3)/(10) miles.

User Fabio Marcolini
by
5.4k points