Answer: Technician should use 11 liters of pure alcohol and technician should use 33 liters of 20% acid solution.
Explanation:
Let the amount of pure alcohol be x
and let the amount of 20% solution be y
So, our first equation will be
![x+y=44](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z05931xgtbnspcpmjos4h99xmfzg3hcnn9.png)
As we have 44 liter batch of 40% of alcohol solution.
And from above equation we can conclude that
![y=44-x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vhatdo6o0bwj11uy31cnizdscao5ilzrhe.png)
According to question,
![1x+0.2y=0.4* 44\\\\x+0.2(44-x)=17.6\\\\x+8.8-0.2x=17.6\\\\0.8x=17.6-8.8\\\\0.8x=8.8\\\\x=(8.)/(0.8)\\\\x=11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/glg84t9sthhka83gd436xne5kdwm8z2dou.png)
Hence, technician should use 11 liters of pure alcohol and
![y=44-x\\\\y=44-11\\\\y=33\ liters](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q35ueg5qgyevbxsmu1p788d0zqn5zout3x.png)
Hence, Technician should use 33 liters of 20% acid solution.