88.4k views
4 votes
Han was looking at the equation 6x−4+2(5x+2)=16x. He said, “I can tell right away there are no solutions, because on the left side, you will have 6x+10x and a bunch of constants, but you have just 16x on the right side.” Do you agree with Han? Explain your reasoning.

User Funkizer
by
6.6k points

2 Answers

4 votes

Answer:

No, I don't agree with Han because there are infinitely many solutions to the equation.

Explanation:

We have been given an equation
6x-4+2(5x+2)=16x. Han said, “I can tell right away there are no solutions, because on the left side, you will have
6x+10x and a bunch of constants, but you have just
16x on the right side.”

We are asked to determine whether Han is right or not.

First of all, we will simplify left side of our given equation as:


6x-4+2\cdot 5x+2\cdot 2=16x


6x-4+10x+4=16x


6x+10x+4-4=16x


16x=16x

Since both sides of equation are equal, so any value of x will make the equation true.

Therefore, there will be infinitely many solution of the equation.

User Ajeet Verma
by
6.4k points
1 vote

Answer:

No, Han is not correct.

Explanation:

In order to question the reasoning of Han, we can start by solving this equation.

6x - 4 + 2(5x + 2) = 16x

Collecting the like terms together and the constant together, we will obtain:

6x + 10x - 16x = 4 - 4

0 *x = 0

This equation has got infinitely many solutions that whatever number you put to the place of x, you will always have zero.

So that, Han's reasoning was not correct.

User Abigblackman
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.