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2 Answers

5 votes

Answer:

The slope-intercept form of the equation is,


y=(1)/(3)x+2

Explanation:

The given equation is


3x+y=-8


Let us make y the subject to obtain,



y=-3x-8


The slope of this line is
-3.


The slope of the line perpendicular to this line should have a slope that is the negative reciprocal of
-3.


The slope of the perpendicular line is


= (-1)/(-3)=(1)/(3)


The slope-intercept form of a line is given by



y=mx+c, where
m=(1)/(3). We substitute this into the equation to obtain,



y=(1)/(3)x+c


Since the line passes through
(-3,1), it must satisfy its equation.


This implies that,


1=(1)/(3)(-3)+c


This simplifies to,



1=-1+c



1+1=c



2=c


We substitute all these values into the equation to get,


y=(1)/(3)x+2










User Kennis
by
8.0k points
3 votes

Answer:

y = 1/3x+2

Explanation:

3x+y = -8

This need to be in slope intercept form, y = mx+b

Subtract 3x from each side

y = -3x-8

The slope is -3

If we want our line to be perpendicular, the slope must be a negative reciprocal.

Take -3, negate it and flip it

-(-1/3) = 1/3

The slope of a perpendicular line is 1/3

We have the slope and a point (-3,1)

We can use point slope form to make a line

y-y1 = m(x-x1)

y-1 = 1/3(x--3)

y-1 = 1/3(x+3)

Distribute

y-1=1/3x+1

Add 1 to each side

y-1 +1= 1/3x+1+1

y = 1/3x+2

This is in slope intercept form

User Arkellys
by
9.1k points

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