2 Answers

Banning · Answer 1 · 2020-06-18T16:18:19+0000

Answer:

$\sqrt[5]{3^3}$

Explanation:

Given:
$27^{(1)/(5) }$

This is the fifth root. We need to write 5 in the index of the radical sign.

$\sqrt[n]{x} = x^(1)/(n)$

Here n is the index of the radical.

$27^{(1)/(5) } = \sqrt[5]{27}$

We can write 27 = 3*3*3 =
3^(3)

$\sqrt[5]{27} = \sqrt[5]{3^3}$

Therefore, the answer is
$27^{(1)/(5) } = \sqrt[5]{3^3}$

Ronny Brendel · Answer 2 · 2020-06-22T20:06:35+0000

Answer:

$27^{(1)/(5) }=\sqrt[5]{3^3}$

Explanation:

we are given

$27^{(1)/(5) }$

we can use rule to change exponent into radical

$\sqrt[n]{a} =a^{(1)/(n) }$

so, we can write as

$27^{(1)/(5)}=(3* 3* 3)^{(1)/(5)}$

$27^{(1)/(5)}=(3^3)^{(1)/(5)}$

now, we can use rule

and we can write our term as

$27^{(1)/(5) }=\sqrt[5]{3^3}$

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