Question

Find the equation of the line perpendicular to the line 4y-x=8 that passes through the points (4,-4)

Answer 1

Hello there,

Find the equation of the line perpendicular to the line 4y-x=8 that passes through the points (4,-4)

Answer:y=-4x+12

Answer 2

y=-4x+12

Explanation:

To find the slope, convert the standard form of the equation into slope intercept form, y=mx+b.

4y-x=8

4y= 8+x

y=1/4x+2

The slope is 1/4 and the slope of the new line will be -4 because the negative reciprocal creates a perpendicular line. Use the point-slope form to write the equation.

(y--4)=-4(x-4)

y+4=-4x+16

y=-4x+12