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Find the equation of the line perpendicular to the line 4y-x=8 that passes through the points (4,-4)

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Hello there,

Find the equation of the line perpendicular to the line 4y-x=8 that passes through the points (4,-4)

Answer:y=-4x+12


User Axalo
by
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5 votes

Answer:

y=-4x+12

Explanation:

To find the slope, convert the standard form of the equation into slope intercept form, y=mx+b.

4y-x=8

4y= 8+x

y=1/4x+2

The slope is 1/4 and the slope of the new line will be -4 because the negative reciprocal creates a perpendicular line. Use the point-slope form to write the equation.

(y--4)=-4(x-4)

y+4=-4x+16

y=-4x+12



User Jeremy Whitcher
by
7.6k points

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