103k views
3 votes
What is the factorization of 1000x^6 - 27?

What is the factorization of 1000x^6 - 27?-example-1
User Larrydag
by
7.9k points

1 Answer

1 vote

Answer:

B

Explanation:

Cube root 1000x^6 = 10x^2

Cube root of - 27 = 3

So the first part of the factorization process is 10x^2 - 3. There is no help here because all of the answers give this binomial as the first factor.

The second factor is (10x^2)^2 + (3)*10x^2 + 3^2)

Expanding you get 100x^4 + 30x^2 + 9

Be very careful when looking at 100x^4 because that is where the answer is found.

It has to be B

User Parlad
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories