Answer:
5/4
Explanation:
To do this you must know that by definition secant is:
![sec(\theta)=(1)/(cos(\theta))](https://img.qammunity.org/2020/formulas/mathematics/high-school/p3u8tqyrg411jhxlj6d1g3yty86rylrgdz.png)
Furthermore:
![sin(\theta)=(opposite)/(hypotenuse)\\\\cos(\theta)=(adjacent)/(hypotenuse)](https://img.qammunity.org/2020/formulas/mathematics/high-school/d2h8npe8tocflp7ghro7y89t4jn9yjtv8l.png)
Based on this information we know that 3 = opposite and 5 = hypotenuse. Assuming this is a right triangle we can determine the adjacent side by Pythagorean Theorem.
![c^2=a^2+b^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xsm8kchig3pfblxfo10xa15jy2ias2waqf.png)
Where c is the hypotenuse, a is adjacent and b is opposite. Therefore,
![c^2=a^2+b^2\\\\a=√(c^2-b^2) \\\\a=√(5^2-3^2) \\\\a=4](https://img.qammunity.org/2020/formulas/mathematics/high-school/cvw0ttlq1vu6bwsuwyigb7w0rc4k0ucj26.png)
And so the adjacent side of this triangle is 4. Going back to the definition of secant we can now know that:
![sec(\theta)=(1)/(cos(\theta))=(1)/((4)/(5))=(5)/(4)](https://img.qammunity.org/2020/formulas/mathematics/high-school/g53cw9cvdhf4di8v495cnh91gru39zdb3p.png)