Answer:
1.After 11 hours, the cruise ship will be _233.75__nautical miles from the lighthouse.
2.At the start of the journey, the cruise ship was _10.5__ nautical miles from the lighthouse.
3.The cruise ship is traveling at a speed of_21.25_ nautical miles per hour.
Explanation:
Distance covered in 2 hours= 95.5-53NM
=42.5NM
therefore,
![Speed= Distance/time................(1)](https://img.qammunity.org/2020/formulas/physics/college/guu1f098eu33mhdg33x6l7jlsnu2fh71nb.png)
put value of distance and time in equation (1)
therefore,
![speed= 42.5/2hour](https://img.qammunity.org/2020/formulas/physics/college/thj501yuvcilf2q2jevdyxk7jc4nxq6ck9.png)
speed=21.25NM/hour
Therefore distance covered in 11 hours= speed* time
![Distance=21.25*11](https://img.qammunity.org/2020/formulas/physics/college/lfgk5ko2tmz6ysiq9tg6tmtdo8yejzjzip.png)
=233.75NM
2. Since distance covered in 2 hours is 42.5
therefore, at starting of the journey the cruise distance from light house is
= 53NM-42.5NM
=10.5NM
3. Distance covered in 2 hours= 95.5-53NM
=42.5NM
therefore,
![Speed= Distance/time................(1)](https://img.qammunity.org/2020/formulas/physics/college/guu1f098eu33mhdg33x6l7jlsnu2fh71nb.png)
put value of distance and time in equation (1)
therefore,
![speed= 42.5/2hour](https://img.qammunity.org/2020/formulas/physics/college/thj501yuvcilf2q2jevdyxk7jc4nxq6ck9.png)
speed=21.25NM/hour
Therefore Cruise ship is traveling at speed of 21.25NM/hour