Answer:
50 mi/h
Explanation:
Given data
- Distance traveled 1 (d1): 120 miles
- Elapsed time 1 (t1): 2.5 hours
- Distance traveled 2 (d2): 105 miles
- Elapsed time 2 (t2): 2 hours
The total distance traveled (d) is:
d = d1 + d2 = 120 mi + 105 mi = 225 mi
The total elpased time (t) is:
t = t1 + t2 = 2.5 h + 2 h = 4.5 h
The average speed of the bus for the entire trip (v) is:
v = d/t = 225 mi/4.5 h = 50 mi/h