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Which logarithmic equation is equivalent to 2^5=32?

User Grub
by
7.7k points

2 Answers

5 votes

Answer:

5 = log₂ 32

Explanation:

When a logarithmic equation is written as b = logₐ c

That means its exponential form is aᵇ = c

In this question exponential expression is given as 2⁵ = 32

By comparing with exponential form given above we find a = 2, b = 5 and c = 32

Now we put these values in the logarithmic equation

5 = log₂ 32 will be the logarithmic equation.

User Mpx
by
6.8k points
3 votes

Answer:
5=log_(2)(32)


Explanation:

1. By definition, you have if
y=b^(x), then
x=log_(b)(y)

2. Keeping this on mind, you must follow the proccedure shown below:

- You have that:


2^(5)=32

Where:


x=5\\y=32\\b=2

- Substitute values into
x=log_(b)(y). Then, you obtain:


5=log_(2)(32)


User Jiayin
by
8.1k points