Question

If s(x)= 2-x^2 and t(x)=3×, which value is equivalent to ( s(t(×)) (-7)

Answer 1

Explanation:

Given that s(x)= 2-x^2 and t(x)=3×

To find which value is equivalent to ( s(t(×)) (-7)

This is composition of functions where t is performed first and then s

x=-7

t(-7)=
`3^(-7)`

NOw s(t(-7))=s(
`3^(-7)`)

=
`2-(3^(-7))^(2) =2-(1)/(3^(14) )`

simplify to get

1.99999