Question

During winter months freshwater fish sense the water getting colder and swim to the bottom of lakes and rivers to find warmer water. If a fish swims seven eights of the depth of a 32-foot deep lake how many feet down did the fish swim

Answer 1

A fish that swims seven eighths of the depth of a 32-foot deep lake swims a total of 28 feet downward to reach warmer waters during winter.

Step-by-step explanation:

When freshwater fish sense the water getting colder during the winter, they instinctively move towards the bottom of lakes and rivers to find warmer areas, which remain liquid due to the property of water being densest at around 4 °C (39.2 °F). If a fish swims seven eighths of the depth of a lake that is 32 feet deep, we perform a calculation to find the distance the fish swam.

To calculate the distance the fish swam, multiply seven eighths (7/8) by the total depth of the lake:

• 7/8 of 32 feet = (7/8) * 32 = 28 feet

Therefore, the fish swam 28 feet down to stay within the warmer, denser water at the bottom of the lake.

Answer 2

Answer: 28 feet.

Step-by-step explanation:

1. To solve this problem you must keep on mind the information given in the problem.

2. You know that fish swims 7/8 of the depth of a 32-foot deep lake. Thererefore, to calculate the number of feet down the fish swam, you must multiply 32 feet by 7/8, as you can see below:

`32feet*(7)/(8)=28feet`

3. Therefore, you can conclude that the fish swam 28 feet down.