Question

The probability of reaching a certain point value in a popular video arcade game is listed in the table. Given that the table is a probability distribution, what is the mean, u? 100 200 300 400 500 600 700 800 P(x) 0.180 0.051 0.227 0.113 0.090 0.099 0.165 0.075

Answer 1

We are given the below probability distribution table:

x P(x)

100 0.180

200 0.051

300 0.227

400 0.113

500 0.090

600 0.099

700 0.165

800 0.075

Now to find the mean, we have to use the below formula:

`Mean, \mu=\sum xP(x)`

`=(100 * 0.180)+(200 * 0.051)+(300 * 0.227)+(400 * 0.113)+(500 * 0.090)+(600 * 0.099)+(700 * 0.165)+(800 * 0.075)`

`=18+10.2+68.1+45.2+45+59.4+115.5+60`

`=421.4`

Therefore, the mean is
`\mu=421.4`