Answer:
5 Adults; 6 Children
Explanation:
If all the tickets purchased were child tickets, the cost would be 11×$35.95 = $384.45. The actual cost is $434.45 -384.45 = $50 more than that.
Changing a child's admission to an adult's admission adds $10 to the cost, so there must have been $50/$10 = 5 adult admissions in the mix. Of course, 11 - 5 = 6, the number of child admissions.
The families bought 5 adult tickets and 6 child tickets.
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Using an equation
Let x represent the number of adult admissions. Then 11-x is the number of child admissions, and the total cost is ...
... 44.95x + 34.95(11 -x) = 434.45
... 10x = 50 . . . . . . . . subtract 384.45 and simplify (compare to the above)
... 50/10 = x = 5 . . . . the number of adult admissions