Question

At 7:30 am a bus left townP for town Q at a speed of 60 klms per hour. 15 minutes later, a car left left town Q and headed for town P. the car reached Town P at 10:45 a.m. the bus reached town Q at noon.

a) What the distance between town P and town Q?
b) What was the speed of the car?

Answer 1

a) 270 km

b) 90 km/h

Explanation:

If a car left left town Q 15 minutes later than bus left town P, then the car left town Q at 7:45 p.m. Since the car reached town P at 10:45 a.m., then the car was
`t_(car)=\{10:45-7:45\}=3` hours on the road.

If a bus left town P at 7:30 and reached town Q at 12:00, then the bus was
`t_(bus)=\{12:00-7:30\}=4(1)/(2)` hours on the road. Since the speed of the bus is 60 km/h, then the distance between towns P and Q is

`D=60\cdot 4.5=270\ km.`

Now the speed of the car is

`v_(car)=(D)/(t_(car))=(270)/(3)=90\ km/h.`