Question

Find the equation of a line that passes through the given points
(-6,-5) and (6,-13)

Answer 1

Hello there,

Find the equation of a line that passes through the given points

(-6,-5) and (6,-13)

Answer: -3/4x-38/4

Answer 2

y+5=-3/4(x+6)

or in slope intercept

y= -3/4x-38/4

Explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

`m=(y_2-y_1)/(x_2-x_1)=(-5--13)/(-6-6)=(-5+13)/(-6+-6)=(8)/(-12)=(-3)/(4)`

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y--5)=-3/4(x--6)

y+5=-3/4(x+6)

y+5=-3/4x-18/4

y=-3/4x-18/4-20/4

y= -3/4x-38/4