Solve the equation (3x–1)(5x+4)–15^2=17

asked Dec 9, 2020 49.8k views

4 votes

by Jemal

5.6k points

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6 votes

Answer:

x=3

Step-by-step explanation:

we have

(3x-1)(5x+4)-15x^2=17

applying the distributive property left side

$(3x-1)(5x+4)-15x^2=17\\15x^(2)+12x-5x-4-15x^(2)=17$

Combine like terms

(15x^(2)-15x^(2))+(12x-5x)=17+4

(0)+(7x)=21

7x=21

x=21/7=3

Psyill answered Dec 15, 2020

5.2k points

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