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pleasse help!!!

1.) A boat costs $16,600 and decreases in value by 14% per year. How much will the boat be worth after 11 years?

a. 16,446.00


b. $70,155.46


c. $3,159.30


d. $2,717.00

2.)Find the first, fourth, and eighth terms of the sequence.
A(n) = −5 ∙ 3x − 1

1; –3,375; –170,859,375


–45; –1,215; –98,415


–5; –135; –10,935


–15; –405; –32,805

1 Answer

3 votes

Answer:

Part 1: C. $3,159.30

Part 2. C. –5; –135; –10,935

Explanation:

Part 1:

Price of the boat = $ 16,600

Depreciation rate = 14% = 0.14

Time of utilization of the boat = 11 years

Price of the boat after 11 years = Original price * (1 - Depreciation rate)^Time of utilization of the boat

Price of the boat after 11 years = 16,600 * (1 - 0.14)¹¹

Price of the boat after 11 years = 16,600 * 0.1903

Price of the boat after 11 years = $ 3,159.30

Part 2:

Let's find out the first term of the sequence given:

A(1) = -5 * 3¹⁻¹

A(1) = -5 * 1

A(1) = -5

Let's find out the fourth term of the sequence given:

A(4) = -5 * 3⁴⁻¹

A(4) = -5 * 3³

A(4) = -5 * 27

A(4) = -135

Let's find out the eighth term of the sequence given:

A(8) = -5 * 3⁸⁻¹

A(8) = -5 * 3⁷

A(8) = -5 * 2,187

A(8) = -10,935

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