Question

mukul has $3.75 in quarters,dimes and nickles in his pocket. he has more dimes than quarters and dimes more nickels than quarters. how many of each coins in his pocket?

Answer 1

Answer: Mukul has 7 quarters, 12 dimes, and 16 nickels.

Explanation:

He has five more dimes than quarters and nine more nickels than quarters, so we let q be the number of quarters, q+5 be the number of dimes, and q+9 be the number of nickels.

Now we have all the information we need from the problem! We multiply the number times the value to get the total value of each type of coin. While we do not know the actual number, we do have an expression to represent it. And so now multiply number⋅value=total value.

Write the equation by adding the total values of all the types of coins.

Value of quarters 0.25q +Value of dimes 0.10 (q+5) +Value of nickels 0.05 (q+9)=total value of coins 3.75

Solving this equation for q gives

0.25q+0.10(q+5)+0.05(q+9)0.25q+0.10q+0.5+0.05q+0.450.4q+0.950.4qq=3.75=3.75=3.75=2.8=7

So, there are 7 quarters. Since the number of dimes is 5 more than the number of quarters, the number of dimes is 7+5=12. Since the number of nickels is 9 more than the number of quarters, the number of nickels is 7+9=16.

Mukul has 7 quarters, 12 dimes, and 16 nickels.

Answer 2

5 quarters, 10 nickels and 20 dimes

Explanation:

There are many possibilities. One of them is:

5 quarters, 10 nickels and 20 dimes.

Number of dimes (20) > Number of quarters (5) and

Number of nickels (10) > Number of quarters (5)

Also,

5 quarters = 5(0.25) = $1.25

10 nickels = 10(0.05) = $0.5

20 dimes = 20(0.1) = $2

1.25 + 0.5 + 2 = 3.75