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Find the solution of this system of equations. x-8y=21 and 3x-8y=15

User Olisch
by
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1 Answer

3 votes

Answer:

x = -3 , y = -3

Explanation:

Solve the following system:

{x - 8 y = 21 | (equation 1)

3 x - 8 y = 15 | (equation 2)

Swap equation 1 with equation 2:

{3 x - 8 y = 15 | (equation 1)

x - 8 y = 21 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{3 x - 8 y = 15 | (equation 1)

0 x - (16 y)/3 = 16 | (equation 2)

Multiply equation 2 by 3/16:

{3 x - 8 y = 15 | (equation 1)

0 x - y = 3 | (equation 2)

Multiply equation 2 by -1:

{3 x - 8 y = 15 | (equation 1)

0 x+y = -3 | (equation 2)

Add 8 × (equation 2) to equation 1:

{3 x+0 y = -9 | (equation 1)

0 x+y = -3 | (equation 2)

Divide equation 1 by 3:

{x+0 y = -3 | (equation 1)

0 x+y = -3 | (equation 2)

Collect results:

Answer: {x = -3 , y = -3

User KarloX
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