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8. What is the domain of
(x)/(x^(2) +20x+75) ? Hint: try factoring the polynomial.

9. What is the domain and range of
√(13x-7)+1 ?

Please hurry! I really need help with this!

User Red Wei
by
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1 Answer

3 votes

Answer:

8. Domain: (-∞, -15) ∪ (-15, -5) ∪ (-5, ∞)

9. Domain: [7/13, ∞)

Range: [1, ∞)

Explanation:

Question 8

Given rational function:


f(x)=(x)/(x^2+20x+75)

Factor the denominator of the given rational function:


\implies x^2+20x+75


\implies x^2+5x+15x+75


\implies x(x+5)+15(x+5)


\implies (x+15)(x+5)

Therefore:


f(x)=(x)/((x+15)(x+5))

Asymptote: a line that the curve gets infinitely close to, but never touches.

The function is undefined when the denominator equals zero:


x+15=0 \implies x=-15


x+5=0 \implies x=-5

Therefore, there are vertical asymptotes at x = -15 and x = -5.

Domain: set of all possible input values (x-values)

Therefore, the domain of the given rational function is:

(-∞, -15) ∪ (-15, -5) ∪ (-5, ∞)

---------------------------------------------------------------------------------

Question 9

Given function:


f(x)=√(13x-7)+1

Domain: set of all possible input values (x-values)

As the square root of a negative number is undefined:


\implies 13x-7\geq 0


\implies 13x\geq 7


\implies x\geq (7)/(13)

Therefore, the domain of the given function is:


\left[(7)/(13),\infty\right)

Range: set of all possible output values (y-values)


\textsf{As }\:√(13x-7)\geq 0


\implies √(13x-7)+1\geq 1

Therefore, the range of the given function is:

[1, ∞)

User Seeta Ram Yadav
by
7.8k points

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