Question

HIII DOES ANYBODY KNOW HOW TO DO #’s 9, 10, and 11? THANK U SM!!!!❤️❤️❤️

Answer 1

9.
`A = 4608~in.^2`

10.
`V = √(5)~ft^3`

11. (a)
`2√(6)~ft`

11. (b)
`perimeter = (6 + 2√(6))~ft`

11. (c)
`area = 3~ft^2`

Explanation:

9. Area of square:

`A = s^2`

`A = (48√(2)~in.)^2`

`A = 48^2 * (√(2))^2~in.^2`

`A = 2304 * 2~in.^2`

`A = 4608~in.^2`

10. Volume of prism:

V = LWH

`V = LWH`

`V = √(5) * (2 + √(3)) * (2 - √(3))~ft^3`

The last two factors are a sum and a difference, so I will multiply them first. The product of a sum and a difference is the difference of two squares.

`V = √(5) * (4 - 3)~ft^3`

`V = √(5) * 1~ft^3`

`V = √(5)~ft^3`

11.

(a) Use the Pythagorean theorem.

`a^2 + b^2 = c^2`

`c^2 = a^2 + b^2`

`c^2 = (3 + √(3))^2 + (3 - √(3))^2`

`c^2 = 9 + 6√(3) + 3 + 9 - 6√(3) + 3`

`c^2 = 9 + 3 + 9 + 3 + 6√(3) - 6√(3)`

`c^2 = 24`

`c = √(24)`

`c = √(4 * 6)`

`c = 2√(6)~ft`

(b) perimeter = sum of lengths of three sides

`perimeter = 3 + √(3) + 3 - √(3) + 2√(6)`

`perimeter = (6 + 2√(6))~ft`

(c) area = base * height/2

The base and height are the legs.

`area = (bh)/(2)`

`area = ((3 + √(3))(3 - √(3)))/(2)`

`area = (9 - 3)/(2)`

`area = (6)/(2)`

`area = 3~ft^2`