Question

A bag of jelly beans contains 10 red,6 green,7 yellow, and 5 orange jelly beans.What is the probability of randomly choosing a red jelly bean,replacing it,randomly choosing another red jelly bean,replacing it,and then randomly choosing an orange jelly bean?

Answer 1

`\text{The Probability is = }(125)/(5488)\approx 0.02`

Explanation:

No. of red jelly = 10

No. of green jelly = 6

No. of yellow jelly = 7

No. of orange jelly = 5

Total number of jelly = 10 + 6 + 7 + 5 = 28

`\text{So, Probability of choosing red jelly, P(R) = }(10)/(28)=(5)/(14)\\\\\text{So, Probability of choosing orange jelly, P(O) = }(5)/(28)\\\\\text{Now, Probability of choosing first red , then red and then orange jelly}\\\text{on replacing each jelly after choosing, }\\\\P(R,R,O) = (5)/(14)* (5)/(14)* (5)/(28)=(125)/(5488)\approx 0.02`

Hence, the required probability is 0.02 or 2 %