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A save percentage in lacrosse is found by dividing the number of saves by the number of shots faced. A lacrosse goalie saved 6 of 13 shots. How many additional consecutive saves s must the goalie make to raise his save percentage to 0.850?

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Answer:

Additional saves = 34 lacrosse.

Explanation:

The additional saves = s

Then , the number of saves becomes = 6+s

and, the number of shots faced = 13+s

Save percentage in lacrosse is found by dividing the number of saves by the number of shots faced that is


\text{ percentage\ in\ lacrosse} =(\text the \ number\ of \ saves)/(\text the \ number of shots faced )


\text{ percentage\ in\ lacrosse} =(6+s)/(13+s )

Given , the percentage of lacrosse = 0.850


{0.850 } =(6+s)/(13+s )


{0.850 *}({13+s })=6+s


11.05+0.850s=6+s


11.05-6=s-0.850s


5.05=0.15s


s=33.66

Since, additional saves must be an integer so round it off to the nearest integer 34.

Thus, Additional saves = 34 lacrosse.

User Vatsal Shukla
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