Question

Use what you know about the difference of squares and the product of a perfect square binomial to expand the following.

Answer 1

`\boxed{x^2 - 6x + 9 - y^2}.`

Explanation:

We start by applying the difference of squares to the expression:

`((x-3)-y)((x-3)+y) = (x-3)^2 - y^2.`

Now we apply the square of a binomial to the first term:

`(x-3)^2 - y^2 = x^2 - 2 * 3 * x + 3^2 - y^2 = x^2 - 6x + 9 - y^2.`

So the answer is:

`\boxed{x^2 - 6x + 9 - y^2}.`