Question

Refer to the balanced equation. (PLEASE HELP QUICK)

8H2S+8Cl2→S8+16HCl

How many L of chlorine gas, at STP, were required if 2.28 mol reacted?

A) 6.38 x 10^0 L Cl2
B) 1.02 x 10^–1 L Cl2
C) 5.12 x 10^1 L Cl2
D) 4.09x 10^2 L Cl2

Answer 1

Answer: C)
`5.12* 10^1` L
`Cl_2`

Explanation:
`8H_2S+8Cl_2\rightarrow S_8+16HCl`

According to Avogadro's law, 1 mole of every gas occupies 22.4 Liters at STP.

Thus from the balanced chemical equation, 8 moles of hydrogen sulfide reacts with 8 moles of chlorine gas.

i.e 8 moles of hydrogen sulfide reacts with
`=8* 22.4L=179.2L` of chlorine gas.

2.28 moles of hydrogen sulfide reacts with
`=(179.2)/(8)* 2.28=51.2L=5.12* 10^1L` of chlorine gas.