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Line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8. Find the probability that a point on JM is placed first on JL and a second point is not placed on KL.

5/8

25/64

8/15

15/64

please help
Anybody!!

2 Answers

0 votes

Answer: The answer is A. 15/64

Explanation:

I got it right! Have a good day!

User Klashar
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4.3k points
2 votes

Answer:

B.
(25)/(64)

Explanation:

Please find the attachment.

We have been given that line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8.

The probability that the first point is positioned on JL would be
(10)/(16) as there are total 10 points on JL as L is at point 8 and J is at point -2 so (8--2=8+2=10). Total number of points on the number line JM is (14--2=14+2=16)

The probability that second point is not placed on KL would be:


P(\text{The point is not on KL)}=1-\text{probability that point is on KL}


P(\text{The point is not on KL)}=1-\frac{\text{Total points on KL}}{\text{Total points on JM}}


P(\text{The point is not on KL)}=1-((8-2))/(16)


P(\text{The point is not on KL)}=1-(6)/(16)


P(\text{The point is not on KL)}=(16-6)/(16)


P(\text{The point is not on KL)}=(10)/(16)


\text{The probability of getting 1st point on Jl and second point is not on KL}=(10)/(16)* (10)/(16)


\text{The probability of getting 1st point on Jl and second point is not on KL}=(5)/(8)* (5)/(8)


\text{The probability of getting 1st point on Jl and second point is not on KL}=(25)/(64)

Therefore, our desired probability will
(25)/(64) and option B is the correct choice.

Line segment JM has endpoints with coordinates -2 and 14 on a number line. Points-example-1
User Atakan
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4.1k points