Question

What is the percent composition of NaHCO3?

Answer 1

Na = 27.37%, H = 1.20%, C = 14.30% and O = 57.14%

Step-by-step explanation:

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Answer 2

Answer:- Na = 27.37%, H = 1.20%, C = 14.30% and O = 57.14%

Solution:- For the percentage composition of a compound, the atomic mass of each atoms times its subscript is divided by the molar mass of the compound and multiplied by 100.

The given compound is
`NaHCO_3`.

mass of Na = 22.99 g

mass of H = 1.008 g

mass of C = 12.01 g

mass of O = 3(16) = 48 g

Molar mass of compound = 22.99 g + 1.008 g + 12.01 g + 48 g = 84.008 g

percentage of Na =
`((22.99)/(84.008))100`

= 27.37%

percentage of H =
`((1.008)/(84.008))100`

= 1.20%

percentage of C =
`((12.01)/(84.008))100`

= 14.30%

percentage of O =
`((48)/(84.008))100`

= 57.14%