Answer:
6 packs of gift bags and 4 packs of bows.
Step-by-step explanation:
We have been give that Rafael wants to buy the same number of gift bags and bows. Gift bags are sold in packs of 6. Bows are sold in packs of 9.
To find the least number of bags and bows that Rafael can but we will find least common multiple of 6 and 9.
Multiples of 6 are: 6, 12 ,18, 24, 30, 36, 42,....
Multiples of 9 are: 9, 18, 27, 36, 45,...
We can see that 36 is the least common multiple of 6 and 9.
![\text{The least number of gift bags Rafael should buy}=(36)/(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wzv3rfsnv5x8mr23klwfgllcakin0qr9n1.png)
![\text{The least number of bows Rafael should buy}=(36)/(9)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2pwr2c2wj73mihs763mzanjijhtp6begnv.png)
![\text{The least number of bows Rafael should buy}=4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h7cixdd7ttcu6o167oz5cafmq8ydx3g5lv.png)
Therefore, Rafael should buy 6 packs of gift bags and 4 packs of bows to have the same number (36) of gift bags and bows.