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Can someone help me with this question

Can someone help me with this question-example-1
User Toffor
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1 Answer

6 votes

Answer:


w = 2.6


x = 26.2^\circ

Explanation:

Solving for w:

Look at the right triangle on the left side. It has a 32-deg angle, a hypotenuse of length 5, and a leg of length w. For the 32-deg angle, w is the opposite leg. We have an opposite leg and a hypotenuse, so we use the sine.


\sin A = (opp)/(hyp)


\sin 32^\circ = (w)/(5)


w = 5 \sin 32^\circ


w = 2.6495


w = 2.6

Solving for x:

Now look at the right triangle on the right side. There is an acute angle measuring x, an opposite leg measuring 2.6495 (from the solution above), and a hypotenuse measuring 6. We use the sine again.


\sin A = (opp)/(hyp)


\sin x = (w)/(6)


\sin x = (2.6495)/(6)


\sin x = 0.441599

Since we know what the sine of angle x is equal to, and we want to know the measure of angle x, we use the inverse sine function, also called the arcsine.


x = \sin^(-1) 0.441599


x = 26.2^\circ

User Ragfield
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