Question

F(x) = 4x + 7, g(x) = 3x2

Find (f + g)(x). (1 point)


3x2 + 4x + 7

-3x2 + 4x + 7

Quantity four x plus 7 divided by three x squared.

12x3 + 21x

Answer 1

(1)

`(f+g)(x)=3x^2+4x+7`

(2)

Explanation:

we are given

`f(x)=4x+7`

`g(x)=3x^2`

we have to find (f+g)(x)

we can write

`(f+g)(x)=f(x)+g(x)`

now, we can plug values

and we get

`(f+g)(x)=4x+7+3x^2`

we can also write as

`(f+g)(x)=3x^2+4x+7`

so, answer is

`(f+g)(x)=3x^2+4x+7`