Question

If a pond has a major axis of 68 feet and a minor axis of 32 feet how far apart are the foci

Answer 1

The distance between foci is 60 feet

Explanation:

we are given

a pond has a major axis of 68 feet

so,
`a=(68)/(2) =34`

a minor axis of 32 feet

so,
`b=(32)/(2) =16`

now, we know ellipse formula

`c^2=a^2-b^2`

where

c is the distance between center and focus

so, we can plug it and find c

`c^2=34^2-16^2`

`c=30`

Distance between foci is

`=2c`

`=2* 30`

`=60`