Question

A circle has a radius of 4/9 units and is centered at (-6.2,5.8)

Write the equation of this circle.

Answer 1

The equation of the circle centered at (-6.2, 5.8) with a radius of 4/9 units is (x + 6.2)^2 + (y - 5.8)^2 = (4/9)^2.

Step-by-step explanation:

The equation of a circle with center at (x,y) and radius r is given by the formula (x - h)^2 + (y - k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. In this case, the center of the circle is at (-6.2, 5.8) and the radius is 4/9 units. Therefore, the equation of the circle is (x + 6.2)^2 + (y - 5.8)^2 = (4/9)^2.

Answer 2

see explanation

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h. k) are the coordinates of the centre and r is the radius

here (h, k ) = (- 6.2, 5.8 ) and r =
`(4)/(9)`, hence

(x + 6.2)² + (y - 5.8)² = (
`(4)/(9)`)²

(x + 6.2)² + (y - 5.8)² =
`(16)/(81)`