Question

Write the expression as a polynomial: (b–c)(b2–bc–c2)(3y–4)

Answer 1

`3b^3y-6b^2cy+3c^3y-4b^3+8b^2c-4c^3`

Explanation:

The given expression is

`(b-c)(b^2-bc-c^2)(3y-4)`.

We expand the first two parenthesis to get,

`(b^3-2b^2c+c^3)(3y-4)`

We now expand again to get,

`3y(b^3-2b^2c+c^3)-4(b^3-2b^2c+c^3)`

This will give us

`3b^3y-6b^2cy+3c^3y-4b^3+8b^2c-4c^3`